What is the solution for y^{''}+y^'=x+2 ?

The solution for y^{''}+y^'=x+2 is y=c_{1}+c_{2}e^{-x}+(x^2)/2+x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+y^'=x+2

y^{^{''}} + y^{^{'}} = x + 2

y = c_{1} + c_{2} e^{- x} + \frac{x ^{2}}{2} + x

Solution steps

y^{''} (x) + y^{'} (x) = x + 2

Solve linear ODE:

y = c_{1} + c_{2} e^{- x} + \frac{x ^{2}}{2} + x

y = c_{1} + c_{2} e^{- x} + \frac{x ^{2}}{2} + x

y^{^{''}} + y^{^{'}} = - 2 x - 3 sin (2 x)

y^{^{''}} + y = 4

y^{^{''}} - 2 y^{^{'}} - 3 y = e^{2 t}

y^{^{''}} + 9 y = 52 e^{2 x}

0.1 y^{^{''}} + 50 y^{^{'}} + 2000 y = 110 cos (377 x)

What is the solution for y^{''}+y^'=x+2 ?
The solution for y^{''}+y^'=x+2 is y=c_{1}+c_{2}e^{-x}+(x^2)/2+x