What is the tangent of f(x)= 4/x ,\at x=-9 ?

The tangent of f(x)= 4/x ,\at x=-9 is y=-4/81 x-8/9

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tangent of f(x)= 4/x ,\at x=-9

tangent of

f (x) = \frac{4}{x}, at x = - 9

y = - \frac{4}{81} x - \frac{8}{9}

Solution steps

Find the tangent point:

(- 9, - \frac{4}{9})

Find the slope of

f (x) = \frac{4}{x} : \frac{df ( x )}{d x} = - \frac{4}{x ^{2}}

Compute the slope of

f (x) = \frac{4}{x}

x = - 9 : m = - \frac{4}{81}

Find the line with slope m=

- \frac{4}{81}

and passing through

(- 9, - \frac{4}{9}) : y = - \frac{4}{81} x - \frac{8}{9}

y = - \frac{4}{81} x - \frac{8}{9}

x \to \infty lim (ln (x!))

\int \frac{2 x ^{2} + 1}{x ( x - 1 ) ^{3}} d x

\frac{d}{d x} ((3 x^{2} - 6 x + 6) e^{x})

n = 1 \sum \infty \frac{3}{4 ^{n}}

\int 3 x^{2} 1 + x^{3} d x

What is the tangent of f(x)= 4/x ,\at x=-9 ?
The tangent of f(x)= 4/x ,\at x=-9 is y=-4/81 x-8/9