What is the solution for y^{''}+10y^'+16=0 ?

The solution for y^{''}+10y^'+16=0 is y=c_{1}+c_{2}e^{-10t}-(8t)/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+10y^'+16=0

y^{^{''}} + 10 y^{^{'}} + 16 = 0

y = c_{1} + c_{2} e^{- 10 t} - \frac{8 t}{5}

Solution steps

y^{''} (t) + 10 y^{'} (t) + 16 = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 10 t} - \frac{8 t}{5}

y = c_{1} + c_{2} e^{- 10 t} - \frac{8 t}{5}

y^{^{''}} + 153.06 y^{^{'}} + 12739.6 y = 191094.97

\frac{d ^{3} y}{d x ^{3}} + y = e^{- x} + 1

\frac{d ^{2} y}{d x ^{2}} + \frac{d y}{d x} - 20 y = e^{- 5 x}

y^{^{''}} - y^{^{'}} - 16 = 0

y^{^{''}} + 40 y^{^{'}} + 6250 y = 100 cos (10 t)

What is the solution for y^{''}+10y^'+16=0 ?
The solution for y^{''}+10y^'+16=0 is y=c_{1}+c_{2}e^{-10t}-(8t)/5