What is the solution for y^{''}+0.01*(20-y)=0 ?

The solution for y^{''}+0.01*(20-y)=0 is y=c_{1}e^{t/(10)}+c_{2}e^{-t/(10)}+20

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y^{''}+0.01*(20-y)=0

y^{^{''}} + 0.01 \cdot (20 - y) = 0

y = c_{1} e^{\frac{t}{10}} + c_{2} e^{- \frac{t}{10}} + 20

Solution steps

y^{''} (t) + 0.01 \cdot (20 - y) = 0

Solve linear ODE:

y = c_{1} e^{\frac{t}{10}} + c_{2} e^{- \frac{t}{10}} + 20

y = c_{1} e^{\frac{t}{10}} + c_{2} e^{- \frac{t}{10}} + 20

y^{^{''}} - 5 y^{^{'}} + 6 y = 6 e^{5 x}

y^{^{''}} + 4 y = 8 e^{2 t}, y (0) = 1, y^{^{'}} (0) = - 2

\frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} = 2 x + 5 - e^{- 2 x}

D (x) = (x - 8)^{2}, S (x) = x^{2} + 2 x + 28

y^{^{''}} + 2 y^{^{'}} = x^{2} + 1

What is the solution for y^{''}+0.01*(20-y)=0 ?
The solution for y^{''}+0.01*(20-y)=0 is y=c_{1}e^{t/(10)}+c_{2}e^{-t/(10)}+20