What is the derivative of (\sqrt[3]{x})/x ?

The derivative of (\sqrt[3]{x})/x is (x^{1/3}-3\sqrt[3]{x})/(3x^2)

What is the first derivative of (\sqrt[3]{x})/x ?

The first derivative of (\sqrt[3]{x})/x is (x^{1/3}-3\sqrt[3]{x})/(3x^2)

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derivative of

Solution steps

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

\frac{d x}{d x} = 1

Simplify

\frac{d}{d x} ((4 x^{2} + 3) (4 x - 5))

\int_{3.5}^{5} \frac{x}{8} d x

\int \frac{- 16}{4 - x ^{2}} d x

\int x (1 - x^{2})^{2} d x

y^{^{''}} + 2 y^{^{'}} + 2 y = 0, y (0) = 1, y^{^{'}} (0) = 0

What is the derivative of (\sqrt[3]{x})/x ?
The derivative of (\sqrt[3]{x})/x is (x^{1/3}-3\sqrt[3]{x})/(3x^2)
What is the first derivative of (\sqrt[3]{x})/x ?
The first derivative of (\sqrt[3]{x})/x is (x^{1/3}-3\sqrt[3]{x})/(3x^2)