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Popular >

2y^{''}-y^'=7

Solution

2 y^{^{''}} - y^{^{'}} = 7

Solution

y = c_{1} e^{\frac{t}{2}} + c_{2} - 7 t

Solution steps

2 y^{''} (t) - y^{'} (t) = 7

Solve linear ODE:

y = c_{1} e^{\frac{t}{2}} + c_{2} - 7 t

y = c_{1} e^{\frac{t}{2}} + c_{2} - 7 t

Graph

Popular Examples

y^{''}+y^'-6y=x^2-x+e^{2x}

y^{^{''}} + y^{^{'}} - 6 y = x^{2} - x + e^{2 x}

y^{''}-10y^'+25y=6e^{-5x}

y^{^{''}} - 10 y^{^{'}} + 25 y = 6 e^{- 5 x}

y^{''}-5y^'+6y=4,e^{4x}y(0)=0,y^'(0)=1

y^{^{''}} - 5 y^{^{'}} + 6 y = 4, e^{4 x} y (0) = 0, y^{^{'}} (0) = 1

(d^2y)/(dx^2)-5(dy)/(dx)-24y=5+2x

\frac{d ^{2} y}{d x ^{2}} - 5 \frac{d y}{d x} - 24 y = 5 + 2 x

y^{''}+y^'-2y=xe^{-2x}+xe^x

y^{^{''}} + y^{^{'}} - 2 y = x e^{- 2 x} + x e^{x}

Frequently Asked Questions (FAQ)

What is the solution for 2y^{''}-y^'=7 ?
The solution for 2y^{''}-y^'=7 is y=c_{1}e^{t/2}+c_{2}-7t