What is the derivative of-2(x^2+3x) ?

The derivative of-2(x^2+3x) is -2(2x+3)

What is the first derivative of-2(x^2+3x) ?

The first derivative of-2(x^2+3x) is -2(2x+3)

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derivative of

- 2 (x^{2} + 3 x)

- 2 (2 x + 3)

Solution steps

\frac{d}{d x} (- 2 (x^{2} + 3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (x^{2} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - 2 (\frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

= - 2 (2 x + 3)

2 t^{2} - 2 t + 1

\frac{d y}{d t} = \frac{2 y}{t}

x^{2} y^{2} \frac{d y}{d x} = 1

f (x) = e^{- x + 1} x - 2 e^{- x + 1}

4 x y = sin (x + y)

What is the derivative of-2(x^2+3x) ?
The derivative of-2(x^2+3x) is -2(2x+3)
What is the first derivative of-2(x^2+3x) ?
The first derivative of-2(x^2+3x) is -2(2x+3)