What is the answer to solvefor d,d(x)=sqrt((2x^3+1)/(x^6)) ?

The answer to solvefor d,d(x)=sqrt((2x^3+1)/(x^6)) is d=(sqrt(2x^3+1))/(x^4);\quad x\ne 0

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solvefor d,d(x)=sqrt((2x^3+1)/(x^6))

solve for

d, d (x) = \frac{2 x ^{3} + 1}{x ^{6}}

d = \frac{2 x ^{3} + 1}{x ^{4}}; x \neq = 0

Solution steps

d (x) = \frac{2 x ^{3} + 1}{x ^{6}}

Divide both sides by

x; x \neq = 0

d = \frac{2 x ^{3} + 1}{x ^{4}}; x \neq = 0

y^{^{''}} + 9 y = 18 cos (3 x)

y^{^{''}} - 2 y^{^{'}} + y = 4 cos (3 x) - 2 sin (2 x)

D^{2} y = 81 y

y^{^{''}} - y^{^{'}} - 6 y = 50 sin (x) - 5 e^{- 2 x}

\frac{d ^{2} x}{d t ^{2}} + 2 \frac{d x}{d t} + 5 x = 1

What is the answer to solvefor d,d(x)=sqrt((2x^3+1)/(x^6)) ?
The answer to solvefor d,d(x)=sqrt((2x^3+1)/(x^6)) is d=(sqrt(2x^3+1))/(x^4);\quad x\ne 0