What is the limit as x approaches 1 of (x^2+1)/(x-1) ?

The limit as x approaches 1 of (x^2+1)/(x-1) is diverges

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limit as x approaches 1 of (x^2+1)/(x-1)

x \to 1 lim (\frac{x ^{2} + 1}{x - 1})

diverges

Solution steps

x \to 1 lim (\frac{x ^{2} + 1}{x - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (\frac{x ^{2} + 1}{x - 1}) = \infty

x \to 1 - lim (\frac{x ^{2} + 1}{x - 1}) = - \infty

= diverges

x \to 3 lim (2 ln (x - 4))

\int 12 (y - 1) x^{3} e^{2 x (y - 1)} d y

\int \frac{4}{( x ^{2} + 1 ) ^{2}} d x

f (x) = (x^{2} - 3) (x^{2} - 2)

What is the limit as x approaches 1 of (x^2+1)/(x-1) ?
The limit as x approaches 1 of (x^2+1)/(x-1) is diverges