en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-y^'=8e^x

Solution

y^{^{''}} - y^{^{'}} = 8 e^{x}

Solution

y = c_{1} e^{x} + c_{2} + 8 x e^{x}

Solution steps

y^{''} (x) - y^{'} (x) = 8 e^{x}

Solve linear ODE:

y = c_{1} e^{x} + c_{2} + 8 x e^{x}

y = c_{1} e^{x} + c_{2} + 8 x e^{x}

Popular Examples

(d^2y)/(dx^2)+4y=4x^2-4x

\frac{d ^{2} y}{d x ^{2}} + 4 y = 4 x^{2} - 4 x

y^{''}-6y^'+9y=16e^7t,y(0)=7,y^'(0)=4

y^{^{''}} - 6 y^{^{'}} + 9 y = 16 e^{7} t, y (0) = 7, y^{^{'}} (0) = 4

y^{''}+6y+34=0,y(0)=3

y^{^{''}} + 6 y + 34 = 0, y (0) = 3

y^{''}+2y^'-3y=3e^{2t}

y^{^{''}} + 2 y^{^{'}} - 3 y = 3 e^{2 t}

y^{''}-3y^'=2x-2

y^{^{''}} - 3 y^{^{'}} = 2 x - 2

Frequently Asked Questions (FAQ)

What is the solution for y^{''}-y^'=8e^x ?
The solution for y^{''}-y^'=8e^x is y=c_{1}e^x+c_{2}+8xe^x