What is the solution for 2y^{''}+14y^'+12y=0.7 ?

The solution for 2y^{''}+14y^'+12y=0.7 is y=c_{1}e^{-t}+c_{2}e^{-6t}+0.05833…

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2y^{''}+14y^'+12y=0.7

2 y^{^{''}} + 14 y^{^{'}} + 12 y = 0.7

y = c_{1} e^{- t} + c_{2} e^{- 6 t} + 0.05833 \dots

Solution steps

2 y^{''} (t) + 14 y^{'} (t) + 12 y = 0.7

Solve linear ODE:

y = c_{1} e^{- t} + c_{2} e^{- 6 t} + 0.05833 \dots

y = c_{1} e^{- t} + c_{2} e^{- 6 t} + 0.05833 \dots

0.25 y^{^{''}} + 10 y^{^{'}} + 1000 = 0

y^{^{''}} - 12 y^{^{'}} + 36 y = 280 sin (x) - 184 cos (x)

y^{^{''}} - 4 y = 8 sin (2 x)

y^{^{''}} + 3 y^{^{'}} - 1 = 0

q^{^{''}} + 100 q^{^{'}} + 2500 q = 30, q (0) = 0, q (0) = 2

What is the solution for 2y^{''}+14y^'+12y=0.7 ?
The solution for 2y^{''}+14y^'+12y=0.7 is y=c_{1}e^{-t}+c_{2}e^{-6t}+0.05833…