What is the solution for y^{''}+9y=12cos(3t) ?

The solution for y^{''}+9y=12cos(3t) is y=c_{1}cos(3t)+c_{2}sin(3t)+2tsin(3t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+9y=12cos(3t)

y^{^{''}} + 9 y = 12 cos (3 t)

y = c_{1} cos (3 t) + c_{2} sin (3 t) + 2 t sin (3 t)

Solution steps

y^{''} (t) + 9 y = 12 cos (3 t)

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t) + 2 t sin (3 t)

y = c_{1} cos (3 t) + c_{2} sin (3 t) + 2 t sin (3 t)

y^{^{''}} + 3 y = e^{2 x}

y^{^{'''}} + 3 y^{^{'}} = sin (x) + 1

y^{^{''}} - 4 y = 12 t^{2} cos^{2} (t)

y^{^{''}} + 3 y^{^{'}} + 2 y = e^{- 2 x} + x

2 x^{^{''}} + 4 x^{^{'}} + 128 x = cos (3 t)

What is the solution for y^{''}+9y=12cos(3t) ?
The solution for y^{''}+9y=12cos(3t) is y=c_{1}cos(3t)+c_{2}sin(3t)+2tsin(3t)