What is the derivative of (350/(sqrt(x^2+y^2))) ?

The derivative of (350/(sqrt(x^2+y^2))) is -(175(2x+2y\frac{dy)/(dx))}{(x^2+y^2)^{3/2}}

What is the first derivative of (350/(sqrt(x^2+y^2))) ?

The first derivative of (350/(sqrt(x^2+y^2))) is -(175(2x+2y\frac{dy)/(dx))}{(x^2+y^2)^{3/2}}

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\frac{d}{d x} (\frac{350}{x ^{2} + y ^{2}})

- \frac{175 ( 2 x + 2 y \frac{d y}{d x} )}{( x ^{2} + y ^{2} ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{350}{x ^{2} + y ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 350 \frac{d}{d x} (\frac{1}{x ^{2} + y ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 350 \frac{d}{d x} ((x^{2} + y^{2})^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( x ^{2} + y ^{2} ) ^{\frac{3}{2}}} \frac{d}{d x} (x^{2} + y^{2})

= - \frac{1}{2 ( x ^{2} + y ^{2} ) ^{\frac{3}{2}}} \frac{d}{d x} (x^{2} + y^{2})

\frac{d}{d x} (x^{2} + y^{2}) = 2 x + 2 y \frac{d y}{d x}

= 350 (- \frac{1}{2 ( x ^{2} + y ^{2} ) ^{\frac{3}{2}}} (2 x + 2 y \frac{d y}{d x}))

Simplify

350 (- \frac{1}{2 ( x ^{2} + y ^{2} ) ^{\frac{3}{2}}} (2 x + 2 y \frac{d y}{d x})) : - \frac{175 ( 2 x + 2 y \frac{d y}{d x} )}{( x ^{2} + y ^{2} ) ^{\frac{3}{2}}}

= - \frac{175 ( 2 x + 2 y \frac{d y}{d x} )}{( x ^{2} + y ^{2} ) ^{\frac{3}{2}}}

(x^{3} e^{- 3 x})^{^{'}}

y = x^{2}

2 \frac{d y}{d x} + \frac{1}{x} y = x^{2} y^{- 1}

\int_{0}^{2} 1 + \frac{5}{4 + x ^{2}} d x

x \to - 8 + lim (\frac{x + 7}{x + 8})

What is the derivative of (350/(sqrt(x^2+y^2))) ?
The derivative of (350/(sqrt(x^2+y^2))) is -(175(2x+2y\frac{dy)/(dx))}{(x^2+y^2)^{3/2}}
What is the first derivative of (350/(sqrt(x^2+y^2))) ?
The first derivative of (350/(sqrt(x^2+y^2))) is -(175(2x+2y\frac{dy)/(dx))}{(x^2+y^2)^{3/2}}