What is the solution for y^{''}(p)+6y^'(p)+9y(p)=p ?

The solution for y^{''}(p)+6y^'(p)+9y(p)=p is y(p)=c_{1}e^{-3p}+c_{2}pe^{-3p}+p/9-2/27

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y^{''}(p)+6y^'(p)+9y(p)=p

y^{^{''}} (p) + 6 y^{^{'}} (p) + 9 y (p) = p

y (p) = c_{1} e^{- 3 p} + c_{2} p e^{- 3 p} + \frac{p}{9} - \frac{2}{27}

Solution steps

y^{''} (p) + 6 y^{'} (p) + 9 y (p) = p

Solve linear ODE:

y (p) = c_{1} e^{- 3 p} + c_{2} p e^{- 3 p} + \frac{p}{9} - \frac{2}{27}

y (p) = c_{1} e^{- 3 p} + c_{2} p e^{- 3 p} + \frac{p}{9} - \frac{2}{27}

y^{^{''}} - 2 y^{^{'}} - 35 y = 768 e^{- t}

y^{^{''}} - y^{^{'}} - 6 y = - e^{x} + 12

y^{^{''}} + 4 y = sec (22 x)

y^{^{''''}} - 2 y^{^{''}} + y = e^{x}

\frac{d ^{2} y}{d x ^{2}} + y = (sec (x))^{3}

What is the solution for y^{''}(p)+6y^'(p)+9y(p)=p ?
The solution for y^{''}(p)+6y^'(p)+9y(p)=p is y(p)=c_{1}e^{-3p}+c_{2}pe^{-3p}+p/9-2/27