What is the solution for y^{''}-0.01y=-0.01*20 ?

The solution for y^{''}-0.01y=-0.01*20 is y=c_{1}e^{t/(10)}+c_{2}e^{-t/(10)}+20

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y^{''}-0.01y=-0.01*20

y^{^{''}} - 0.01 y = - 0.01 \cdot 20

y = c_{1} e^{\frac{t}{10}} + c_{2} e^{- \frac{t}{10}} + 20

Solution steps

y^{''} (t) - 0.01 y = - 0.01 \cdot 20

Solve linear ODE:

y = c_{1} e^{\frac{t}{10}} + c_{2} e^{- \frac{t}{10}} + 20

y = c_{1} e^{\frac{t}{10}} + c_{2} e^{- \frac{t}{10}} + 20

y^{^{''}} + \frac{1}{2} y^{^{'}} + y = 4 sin (\frac{x}{2})

y^{^{'''}} - y = x^{3} - 1

8 y^{^{''}} + y = t, y (0) = 0, y^{^{'}} (0) = 0

y^{^{''}} - 4 y = t e^{4 t}

y^{^{''}} + y^{^{'}} + \frac{256}{3} x = 50 cos (3 x)

What is the solution for y^{''}-0.01y=-0.01*20 ?
The solution for y^{''}-0.01y=-0.01*20 is y=c_{1}e^{t/(10)}+c_{2}e^{-t/(10)}+20