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Popular >

y^{''}+6y^'=-9

Solution

y^{^{''}} + 6 y^{^{'}} = - 9

Solution

y = c_{1} + c_{2} e^{- 6 t} - \frac{3 t}{2}

Solution steps

y^{''} (t) + 6 y^{'} (t) = - 9

Solve linear ODE:

y = c_{1} + c_{2} e^{- 6 t} - \frac{3 t}{2}

y = c_{1} + c_{2} e^{- 6 t} - \frac{3 t}{2}

Popular Examples

y^{''}+4y^'+8y=24,y^'(0)=0,y(0)=0

y^{^{''}} + 4 y^{^{'}} + 8 y = 24, y^{^{'}} (0) = 0, y (0) = 0

y^{''}+18y^'-y=t^{-1}e^t

y^{^{''}} + 18 y^{^{'}} - y = t^{- 1} e^{t}

DB=10log_{10}((0.1)/(1*10^{-12)})

D B = 10 lo g_{10} (\frac{0.1}{1 \cdot 1 0 ^{- 12}})

y^{''}-8y^'+16y=32t+64,y(0)=3,y^'(0)=-3

y^{^{''}} - 8 y^{^{'}} + 16 y = 32 t + 64, y (0) = 3, y^{^{'}} (0) = - 3

y^{''}+4y^'+40y=12.5sin(6t)

y^{^{''}} + 4 y^{^{'}} + 40 y = 12.5 sin (6 t)

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+6y^'=-9 ?
The solution for y^{''}+6y^'=-9 is y=c_{1}+c_{2}e^{-6t}-(3t)/2