What is the solution for y^{'''}-3y^{''}-y^'+3y=e^x ?

The solution for y^{'''}-3y^{''}-y^'+3y=e^x is y=c_{1}e^{3x}+c_{2}e^{-x}+c_{3}e^x-(e^xx)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{'''}-3y^{''}-y^'+3y=e^x

y^{^{'''}} - 3 y^{^{''}} - y^{^{'}} + 3 y = e^{x}

y = c_{1} e^{3 x} + c_{2} e^{- x} + c_{3} e^{x} - \frac{e ^{x} x}{4}

Solution steps

y^{'''} (x) - 3 y^{''} (x) - y^{'} (x) + 3 y = e^{x}

Solve linear ODE:

y = c_{1} e^{3 x} + c_{2} e^{- x} + c_{3} e^{x} - \frac{e ^{x} x}{4}

y = c_{1} e^{3 x} + c_{2} e^{- x} + c_{3} e^{x} - \frac{e ^{x} x}{4}

y^{^{''}} + 9 y = sin (2.9 t), y (0) = 1, y^{^{'}} (0) = 1

y^{^{''}} + 4 y = 11 sec^{2} (2 t)

y^{^{''}} - 5 y^{^{'}} + 4 y = 2 e^{x} + x + 1

4 y^{^{''}} - 8 y^{^{'}} + 3 = 0, y (0) = 2, y^{^{'}} (0) = \frac{1}{2}

y^{^{'''}} - 9 y^{^{''}} + 27 y = 3 e^{3 x}

What is the solution for y^{'''}-3y^{''}-y^'+3y=e^x ?
The solution for y^{'''}-3y^{''}-y^'+3y=e^x is y=c_{1}e^{3x}+c_{2}e^{-x}+c_{3}e^x-(e^xx)/4