What is the answer to solvefor d,d(x)=(k(x)+18x-9)/(2x^2) ?

The answer to solvefor d,d(x)=(k(x)+18x-9)/(2x^2) is d=(kx+18x-9)/(2x^3);\quad x\ne 0

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solvefor d,d(x)=(k(x)+18x-9)/(2x^2)

solve for

d, d (x) = \frac{k ( x ) + 18 x - 9}{2 x ^{2}}

d = \frac{k x + 18 x - 9}{2 x ^{3}}; x \neq = 0

Solution steps

d (x) = \frac{k ( x ) + 18 x - 9}{2 x ^{2}}

d x = \frac{k x + 18 x - 9}{2 x ^{2}}

Divide both sides by

x; x \neq = 0

d = \frac{k x + 18 x - 9}{2 x ^{3}}; x \neq = 0

y^{^{'''}} + 3 y^{^{''}} - 4 y = x e^{x} + 14 x

y^{^{''}} - 2 y^{^{'}} = - 6 x^{2} + 1

y^{^{''}} + y^{^{'}} + 0.25 y = e^{x} (sin (3 x) - cos (3 x))

y^{^{''}} + 4 y^{^{'}} = t^{2} + 6 e^{t}, y (0) = 0, y^{^{'}} (0) = 9

y^{^{''}} + 4 y^{^{'}} = t^{2} + 6 e^{t}, y (0) = 0, y^{^{'}} (0) = 5

What is the answer to solvefor d,d(x)=(k(x)+18x-9)/(2x^2) ?
The answer to solvefor d,d(x)=(k(x)+18x-9)/(2x^2) is d=(kx+18x-9)/(2x^3);\quad x\ne 0