What is the limit as h approaches+0 of (|h|)/h ?

The limit as h approaches+0 of (|h|)/h is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as h approaches+0 of (|h|)/h

h \to + 0 lim (\frac{∣ h ∣}{h})

diverges

Solution steps

h \to 0 lim (\frac{∣ h ∣}{h})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

h \to 0 + lim (\frac{∣ h ∣}{h}) = 1

h \to 0 - lim (\frac{∣ h ∣}{h}) = - 1

= diverges

\int \frac{ln ( x ) sin ( ln ( x ) )}{x} d x

x \to 1 lim (\frac{x - 1}{x + 1})

\int \frac{e ^{2 x}}{e ^{x} + 3} d x

\frac{\partial}{\partial x} (x ln (x + 7 y))

f (x) = (x^{2} + 8) (7 - x)

What is the limit as h approaches+0 of (|h|)/h ?
The limit as h approaches+0 of (|h|)/h is diverges