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Popular >

y^{''}+5y^'=2

Solution

y^{^{''}} + 5 y^{^{'}} = 2

Solution

y = c_{1} + c_{2} e^{- 5 t} + \frac{2 t}{5}

Solution steps

y^{''} (t) + 5 y^{'} (t) = 2

Solve linear ODE:

y = c_{1} + c_{2} e^{- 5 t} + \frac{2 t}{5}

y = c_{1} + c_{2} e^{- 5 t} + \frac{2 t}{5}

Graph

Popular Examples

y^{''}+6y^'+9y=3x+5,y(0)=1,y^'(0)=-1

y^{^{''}} + 6 y^{^{'}} + 9 y = 3 x + 5, y (0) = 1, y^{^{'}} (0) = - 1

y^{''}+2y^'+5y=2+e^x

y^{^{''}} + 2 y^{^{'}} + 5 y = 2 + e^{x}

y^{^{''}} + 2 y = - 3

y^{''}+8y=2t^2-2,y(0)=0,y^'(0)=-5

y^{^{''}} + 8 y = 2 t^{2} - 2, y (0) = 0, y^{^{'}} (0) = - 5

y^{''}+25y=64cos(3x),y(0)=0,y^'(0)=0

y^{^{''}} + 25 y = 64 cos (3 x), y (0) = 0, y^{^{'}} (0) = 0

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+5y^'=2 ?
The solution for y^{''}+5y^'=2 is y=c_{1}+c_{2}e^{-5t}+(2t)/5