What is the solution for y^{''}-y=-11t+4 ?

The solution for y^{''}-y=-11t+4 is y=c_{1}e^t+c_{2}e^{-t}+11t-4

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y^{''}-y=-11t+4

y^{^{''}} - y = - 11 t + 4

y = c_{1} e^{t} + c_{2} e^{- t} + 11 t - 4

Solution steps

y^{''} (t) - y = - 11 t + 4

Solve linear ODE:

y = c_{1} e^{t} + c_{2} e^{- t} + 11 t - 4

y = c_{1} e^{t} + c_{2} e^{- t} + 11 t - 4

(x^{^{''}} + 2 x^{^{'}} + 5)^{3} = 0

y^{^{''}} + 9 y = 9 \cdot sec^{2} (3 t)

y^{^{''}} + 25 y = 13 sec (5 t)

x^{^{''}} + 3 x^{^{'}} + 2 x = 3 (e^{(- 3 t)})

\frac{d ^{2} y}{d x ^{2}} + 4 y = cos (2 x)

What is the solution for y^{''}-y=-11t+4 ?
The solution for y^{''}-y=-11t+4 is y=c_{1}e^t+c_{2}e^{-t}+11t-4