What is the solution for y^{''}-2y+2=0 ?

The solution for y^{''}-2y+2=0 is y=c_{1}e^{sqrt(2)t}+c_{2}e^{-sqrt(2)t}+1

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y^{''}-2y+2=0

y^{^{''}} - 2 y + 2 = 0

y = c_{1} e^{2 t} + c_{2} e^{- 2 t} + 1

Solution steps

y^{''} (t) - 2 y + 2 = 0

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} e^{- 2 t} + 1

y = c_{1} e^{2 t} + c_{2} e^{- 2 t} + 1

y^{^{''}} + 2 y^{^{'}} + 5 y = 25

y^{^{'''}} + 4 y^{^{''}} + 8 y^{^{'}} = 11 + 5 e^{2 x}

y^{^{''}} - 9 y^{^{'}} = 81 x^{2} + 7, y (0) = - 1, y^{^{'}} (0) = 2

y^{^{''}} - y^{^{'}} - 6 y = 14 sin (3)

y^{^{''}} - 4 y + 3 y = 9 x^{2}

What is the solution for y^{''}-2y+2=0 ?
The solution for y^{''}-2y+2=0 is y=c_{1}e^{sqrt(2)t}+c_{2}e^{-sqrt(2)t}+1