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Popular >

y^{''}=4+(y^')2

Solution

y^{^{''}} = 4 + (y^{^{'}}) 2

Solution

y = c_{1} e^{2 t} + c_{2} - 2 t

Solution steps

y^{''} (t) = 4 + (y^{'} (t)) 2

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} - 2 t

y = c_{1} e^{2 t} + c_{2} - 2 t

Graph

Popular Examples

y^{''}-y=e^{2x}*e^{e^x}

y^{^{''}} - y = e^{2 x} \cdot e^{e^{x}}

y^{''}+9y=4((u^5)/3 pi-\H(13/3)pi)

y^{^{''}} + 9 y = 4 (\frac{u ^{5}}{3} π - H (\frac{13}{3}) π)

y^{''}-y=13t,y(0)=-13t

y^{^{''}} - y = 13 t, y (0) = - 13 t

y^{''}+y=sqrt(2)sin(sqrt(2)t),y^'(0)=10

y^{^{''}} + y = 2 sin (2 t), y^{^{'}} (0) = 10

y^{^{''}} - y^{^{'}} = x^{3}

Frequently Asked Questions (FAQ)

What is the solution for y^{''}=4+(y^')2 ?
The solution for y^{''}=4+(y^')2 is y=c_{1}e^{2t}+c_{2}-2t