What is the solution for y^{''}-y=2e^{-x} ?

The solution for y^{''}-y=2e^{-x} is y=c_{1}e^x+c_{2}e^{-x}-e^{-x}x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-y=2e^{-x}

y^{^{''}} - y = 2 e^{- x}

y = c_{1} e^{x} + c_{2} e^{- x} - e^{- x} x

Solution steps

y^{''} (x) - y = 2 e^{- x}

Solve linear ODE:

y = c_{1} e^{x} + c_{2} e^{- x} - e^{- x} x

y = c_{1} e^{x} + c_{2} e^{- x} - e^{- x} x

x^{^{''}} - 4 x^{^{'}} + 4 x = 2

y^{^{''}} + 8 y^{^{'}} + 15 y = 3 e^{- 3 t}

y^{^{''}} - y^{^{'}} - 12 y = - 5 e^{3 x}

y^{^{''}} + 5 y^{^{'}} + 4 = 0

\frac{d ^{2} y}{d x ^{2}} + y = 3 cos (2 x)

What is the solution for y^{''}-y=2e^{-x} ?
The solution for y^{''}-y=2e^{-x} is y=c_{1}e^x+c_{2}e^{-x}-e^{-x}x