What is the solution for (dy}{dx}=\frac{x^4)/y ?

The solution for (dy}{dx}=\frac{x^4)/y is y=sqrt((2x^5)/5+c_{1)},y=-sqrt((2x^5)/5+c_{1)}

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(dy}{dx}=\frac{x^4)/y

\frac{d y}{d x} = \frac{x ^{4}}{y}

y = \frac{2 x ^{5}}{5} + c_{1}, y = - \frac{2 x ^{5}}{5} + c_{1}

Solution steps

\frac{d y}{d x} = \frac{x ^{4}}{y}

Solve separable ODE:

y = \frac{2 x ^{5}}{5} + c_{1}, y = - \frac{2 x ^{5}}{5} + c_{1}

y = \frac{2 x ^{5}}{5} + c_{1}, y = - \frac{2 x ^{5}}{5} + c_{1}

x \to 2 lim (x^{2} + 2 x - 5)

\int - 2 + 18 x - 12 x^{2} d x

x \to 0 lim (10 x ln (x))

\frac{d}{d x} ((2 x - 5)^{4} (x^{2} + x + 1)^{5})

\frac{d}{d x} (8 x^{3} - x^{5})

What is the solution for (dy}{dx}=\frac{x^4)/y ?
The solution for (dy}{dx}=\frac{x^4)/y is y=sqrt((2x^5)/5+c_{1)},y=-sqrt((2x^5)/5+c_{1)}