What is the solution for y^{''}+5y^'-y=11 ?

The solution for y^{''}+5y^'-y=11 is y=c_{1}e^{((-5+sqrt(29))t)/2}+c_{2}e^{((-5-sqrt(29))t)/2}-11

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y^{''}+5y^'-y=11

y^{^{''}} + 5 y^{^{'}} - y = 11

y = c_{1} e^{\frac{( - 5 + 29 ) t}{2}} + c_{2} e^{\frac{( - 5 - 29 ) t}{2}} - 11

Solution steps

y^{''} (t) + 5 y^{'} (t) - y = 11

Solve linear ODE:

y = c_{1} e^{\frac{( - 5 + 29 ) t}{2}} + c_{2} e^{\frac{( - 5 - 29 ) t}{2}} - 11

y = c_{1} e^{\frac{( - 5 + 29 ) t}{2}} + c_{2} e^{\frac{( - 5 - 29 ) t}{2}} - 11

100 y^{^{''}} + 13 y^{^{'}} + \frac{6 y}{25} = 600

y^{^{''}} + y^{^{'}} - y = 2

y^{^{''}} + y^{^{'}} - 2 y = 4 e^{2 t}, y (0) = 1, y^{^{'}} (0) = - 1

y^{^{''}} + 3 y + 2 = 0

y^{^{''}} - 14 y^{^{'}} + 49 y = 21 x + 6

What is the solution for y^{''}+5y^'-y=11 ?
The solution for y^{''}+5y^'-y=11 is y=c_{1}e^{((-5+sqrt(29))t)/2}+c_{2}e^{((-5-sqrt(29))t)/2}-11