What is the solution for y^{''}+3y=11 ?

The solution for y^{''}+3y=11 is y=c_{1}cos(sqrt(3)t)+c_{2}sin(sqrt(3)t)+11/3

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y^{''}+3y=11

y^{^{''}} + 3 y = 11

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{11}{3}

Solution steps

y^{''} (t) + 3 y = 11

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{11}{3}

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{11}{3}

x^{^{''}} + 2 x^{^{'}} + 2 x = 2, x (0) = 0, x^{^{'}} (0) = 0

(d^{2} - 4 d + 3) y = e^{2 t}

y^{^{''}} = 2 y + tan^{3} (x), y^{1} (x) = \frac{1}{2} tan (x)

y^{^{''}} - 2 y + y = \frac{e ^{x}}{1 + x ^{2}}

y^{^{''}} - 11 y^{^{'}} + 28 y = 108 e^{t}

What is the solution for y^{''}+3y=11 ?
The solution for y^{''}+3y=11 is y=c_{1}cos(sqrt(3)t)+c_{2}sin(sqrt(3)t)+11/3