What is the solution for y^{''}+6y^'+5y=10cos(5x) ?

The solution for y^{''}+6y^'+5y=10cos(5x) is y=c_{1}e^{-x}+c_{2}e^{-5x}+3/13 sin(5x)-2/13 cos(5x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+6y^'+5y=10cos(5x)

y^{^{''}} + 6 y^{^{'}} + 5 y = 10 cos (5 x)

y = c_{1} e^{- x} + c_{2} e^{- 5 x} + \frac{3}{13} sin (5 x) - \frac{2}{13} cos (5 x)

Solution steps

y^{''} (x) + 6 y^{'} (x) + 5 y = 10 cos (5 x)

Solve linear ODE:

y = c_{1} e^{- x} + c_{2} e^{- 5 x} + \frac{3}{13} sin (5 x) - \frac{2}{13} cos (5 x)

y = c_{1} e^{- x} + c_{2} e^{- 5 x} + \frac{3}{13} sin (5 x) - \frac{2}{13} cos (5 x)

y^{^{''}} + y = 2 x + 4

\frac{d ^{2} y}{d x ^{2}} - 5 \frac{d y}{d x} + 4 y = sin (x)

y^{^{''}} + 16 y = - 16 sec (4 t)

\frac{d ^{2} y}{d x ^{2}} - 10 \cdot \frac{d y}{d x} + 25 \cdot y = 30 \cdot x + 3

y^{^{''}} - 5 y^{^{'}} = 28 x e^{- 2 x} + 10

What is the solution for y^{''}+6y^'+5y=10cos(5x) ?
The solution for y^{''}+6y^'+5y=10cos(5x) is y=c_{1}e^{-x}+c_{2}e^{-5x}+3/13 sin(5x)-2/13 cos(5x)