What is the solution for y^{''}-9y^'+20y=6x+e^{4x} ?

The solution for y^{''}-9y^'+20y=6x+e^{4x} is y=c_{1}e^{5x}+c_{2}e^{4x}+(3x)/(10)+27/200-e^{4x}x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-9y^'+20y=6x+e^{4x}

y^{^{''}} - 9 y^{^{'}} + 20 y = 6 x + e^{4 x}

y = c_{1} e^{5 x} + c_{2} e^{4 x} + \frac{3 x}{10} + \frac{27}{200} - e^{4 x} x

Solution steps

y^{''} (x) - 9 y^{'} (x) + 20 y = 6 x + e^{4 x}

Solve linear ODE:

y = c_{1} e^{5 x} + c_{2} e^{4 x} + \frac{3 x}{10} + \frac{27}{200} - e^{4 x} x

y = c_{1} e^{5 x} + c_{2} e^{4 x} + \frac{3 x}{10} + \frac{27}{200} - e^{4 x} x

y^{^{''}} + 9 y = 16 sin (3 x) + 12 cos (3 x)

2 x^{^{''}} + 5 x^{^{'}} + 2 x = 10 sin (t)

y^{^{''}} - 4 y^{^{'}} - 12 y = 3 e^{5} t

y^{^{'''}} - 4 y^{^{''}} - y^{^{'}} + 4 y = e^{6 x}

y^{^{''}} + 36 y = 2 cos (6 x) + 3 sin (6 x)

What is the solution for y^{''}-9y^'+20y=6x+e^{4x} ?
The solution for y^{''}-9y^'+20y=6x+e^{4x} is y=c_{1}e^{5x}+c_{2}e^{4x}+(3x)/(10)+27/200-e^{4x}x