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Popular >

derivative of 1/2 x^6-3x^4+x

Solution

\frac{d}{d x} (\frac{1}{2} x^{6} - 3 x^{4} + x)

Solution

3 x^{5} - 12 x^{3} + 1

Solution steps

\frac{d}{d x} (\frac{1}{2} x^{6} - 3 x^{4} + x)

Simplify

\frac{1}{2} x^{6} - 3 x^{4} + x : \frac{x ^{6}}{2} - 3 x^{4} + x

= \frac{d}{d x} (\frac{x ^{6}}{2} - 3 x^{4} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{6}}{2}) - \frac{d}{d x} (3 x^{4}) + \frac{d x}{d x}

\frac{d}{d x} (\frac{x ^{6}}{2}) = 3 x^{5}

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d x}{d x} = 1

= 3 x^{5} - 12 x^{3} + 1

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x \to π - lim ((x - π) cot (x))

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\int 3 sin (2 x) d x

16(d^4y)/(dx^4)+48(d^2y)/(dx^2)+36y=0

16 \frac{d ^{4} y}{d x ^{4}} + 48 \frac{d ^{2} y}{d x ^{2}} + 36 y = 0

area x,x^2-4x+3 area

x, x^{2} - 4 x + 3

Frequently Asked Questions (FAQ)

What is the derivative of 1/2 x^6-3x^4+x ?
The derivative of 1/2 x^6-3x^4+x is 3x^5-12x^3+1
What is the first derivative of 1/2 x^6-3x^4+x ?
The first derivative of 1/2 x^6-3x^4+x is 3x^5-12x^3+1