What is the derivative of 7/(1+7x) ?

The derivative of 7/(1+7x) is -(49)/((1+7x)^2)

What is the first derivative of 7/(1+7x) ?

The first derivative of 7/(1+7x) is -(49)/((1+7x)^2)

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\frac{d}{d x} (\frac{7}{1 + 7 x})

- \frac{49}{( 1 + 7 x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{7}{1 + 7 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (\frac{1}{1 + 7 x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 7 \frac{d}{d x} ((1 + 7 x)^{- 1})

Apply the chain rule:

- \frac{1}{( 1 + 7 x ) ^{2}} \frac{d}{d x} (1 + 7 x)

= - \frac{1}{( 1 + 7 x ) ^{2}} \frac{d}{d x} (1 + 7 x)

\frac{d}{d x} (1 + 7 x) = 7

= 7 (- \frac{1}{( 1 + 7 x ) ^{2}} \cdot 7)

Simplify

7 (- \frac{1}{( 1 + 7 x ) ^{2}} \cdot 7) : - \frac{49}{( 1 + 7 x ) ^{2}}

= - \frac{49}{( 1 + 7 x ) ^{2}}

x \to 6 lim (\frac{x ^{2} - 5}{x - 6})

18 x y^{^{'}} - ln (x^{6}) = 0, y (1) = 12

f (x) = x^{2} 3 x + 5

\frac{\partial}{\partial x} (- arctan (\frac{x}{y}))

n = 0 \sum \infty (\frac{5}{4})^{n}

What is the derivative of 7/(1+7x) ?
The derivative of 7/(1+7x) is -(49)/((1+7x)^2)
What is the first derivative of 7/(1+7x) ?
The first derivative of 7/(1+7x) is -(49)/((1+7x)^2)