What is the solution for y^{''}+y=e^3+e^{2x} ?

The solution for y^{''}+y=e^3+e^{2x} is y=c_{1}cos(x)+c_{2}sin(x)+e^3+1/5 e^{2x}

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y^{''}+y=e^3+e^{2x}

y^{^{''}} + y = e^{3} + e^{2 x}

y = c_{1} cos (x) + c_{2} sin (x) + e^{3} + \frac{1}{5} e^{2 x}

Solution steps

y^{''} (x) + y = e^{3} + e^{2 x}

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) + e^{3} + \frac{1}{5} e^{2 x}

y = c_{1} cos (x) + c_{2} sin (x) + e^{3} + \frac{1}{5} e^{2 x}

y^{^{''}} + 6 y + 34 = 0, y (0) = 1, y^{^{'}} (0) = 7

y^{^{''}} + 25 y = 2 cos (5.1 t), y (0) = 1, y^{^{'}} (0) = 1

y^{^{''}} + 256 y = 20 sin (16 x)

2 y^{^{'}} - 3 = - y + y^{^{''}} + 16 e^{3 x} + 3 e^{2 x} + 5

y^{^{''}} + 2 y^{^{'}} - 3 y = 6 x - 3 e^{2 x}

What is the solution for y^{''}+y=e^3+e^{2x} ?
The solution for y^{''}+y=e^3+e^{2x} is y=c_{1}cos(x)+c_{2}sin(x)+e^3+1/5 e^{2x}