What is the solution for x^{''}-25x=6t ?

The solution for x^{''}-25x=6t is x=c_{1}e^{5t}+c_{2}e^{-5t}-(6t)/(25)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{''}-25x=6t

x^{^{''}} - 25 x = 6 t

x = c_{1} e^{5 t} + c_{2} e^{- 5 t} - \frac{6 t}{25}

Solution steps

x^{''} (t) - 25 x = 6 t

Solve linear ODE:

x = c_{1} e^{5 t} + c_{2} e^{- 5 t} - \frac{6 t}{25}

x = c_{1} e^{5 t} + c_{2} e^{- 5 t} - \frac{6 t}{25}

x^{^{''}} - 4 x^{^{'}} + 4 x = e^{t} + e^{2 t} + 1

\frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} + 10 y = 2 cos (6 x)

y^{^{''}} + 25 y = sec^{3} (5 x)

y^{^{''}} - 3 y^{^{'}} + 2 y = sin (3 x), y (0) = 1, y^{^{'}} (0) = 0

y^{^{''}} + 2 y^{^{'}} + 2 y = (cos (x)) e^{- x}

What is the solution for x^{''}-25x=6t ?
The solution for x^{''}-25x=6t is x=c_{1}e^{5t}+c_{2}e^{-5t}-(6t)/(25)