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Popular >

y^{''}+y^'-2=0

Solution

y^{^{''}} + y^{^{'}} - 2 = 0

Solution

y = c_{1} + c_{2} e^{- t} + 2 t

Solution steps

y^{''} (t) + y^{'} (t) - 2 = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- t} + 2 t

y = c_{1} + c_{2} e^{- t} + 2 t

Graph

Popular Examples

-y^{''}+y^'+6y=1-x

- y^{^{''}} + y^{^{'}} + 6 y = 1 - x

y''-3y'+2y=11^{(e^3x)}

y^{''} - 3 y^{'} + 2 y = 1 1^{(e^{3} x)}

y^{''}-2y^'+y=(3e^t)/(t^2+1)

y^{^{''}} - 2 y^{^{'}} + y = \frac{3 e ^{t}}{t ^{2} + 1}

y^{''}-36y=180t-72e^{-1},y(0)=0,y^'(0)=61

y^{^{''}} - 36 y = 180 t - 72 e^{- 1}, y (0) = 0, y^{^{'}} (0) = 61

(d^2y)/(dt^2)+2(dy)/(dt)+4y=13t^3

\frac{d ^{2} y}{d t ^{2}} + 2 \frac{d y}{d t} + 4 y = 13 t^{3}

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+y^'-2=0 ?
The solution for y^{''}+y^'-2=0 is y=c_{1}+c_{2}e^{-t}+2t