What is the answer to solvefor d,d(x)=log_{10}((x+4)/(x-1)) ?

The answer to solvefor d,d(x)=log_{10}((x+4)/(x-1)) is d=(log_{10}((x+4)/(x-1)))/x ;\quad x\ne 0

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solvefor d,d(x)=log_{10}((x+4)/(x-1))

solve for

d, d (x) = lo g_{10} (\frac{x + 4}{x - 1})

d = \frac{lo g _{10} ( \frac{x + 4}{x - 1} )}{x}; x \neq = 0

Solution steps

d (x) = lo g_{10} (\frac{x + 4}{x - 1})

Divide both sides by

x; x \neq = 0

d = \frac{lo g _{10} ( \frac{x + 4}{x - 1} )}{x}; x \neq = 0

y^{^{''}} + 4 y^{^{'}} + y = 4

a y^{^{''}} + b y^{^{'}} = 1

y^{^{''}} - 2 y^{^{'}} + 2 y = sec (x) e^{x}

(D^{3} - D) y = x^{3}

y^{^{''}} - 2 y = x + 1

What is the answer to solvefor d,d(x)=log_{10}((x+4)/(x-1)) ?
The answer to solvefor d,d(x)=log_{10}((x+4)/(x-1)) is d=(log_{10}((x+4)/(x-1)))/x ;\quad x\ne 0