What is the solution for (D^2+5)y=cos(sqrt(5))x ?

The solution for (D^2+5)y=cos(sqrt(5))x is y=c_{1}cos(sqrt(5)x)+c_{2}sin(sqrt(5)x)+(cos(sqrt(5))x)/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(D^2+5)y=cos(sqrt(5))x

(D^{2} + 5) y = cos (5) x

y = c_{1} cos (5 x) + c_{2} sin (5 x) + \frac{cos ( 5 ) x}{5}

Solution steps

(D^{2} + 5) y = cos (5) x

Solve linear ODE:

y = c_{1} cos (5 x) + c_{2} sin (5 x) + \frac{cos ( 5 ) x}{5}

y = c_{1} cos (5 x) + c_{2} sin (5 x) + \frac{cos ( 5 ) x}{5}

(D^{2} + 4 D + 4) y = 5 e^{3 x}

3 y^{^{'}} + 2 y^{^{''}} = - 1000 cos (3.14 \cdot \frac{t}{0.2})

y^{^{''}} - \frac{1}{2} y^{^{'}} - 1 = 0, y (0) = 100, y (3) = 10

\frac{1}{2} y^{^{''}} + 2 y = 3 tan (2 t) - \frac{1}{2} e^{2 t}

y^{^{''}} + 4 y^{^{'}} + y = - 9

What is the solution for (D^2+5)y=cos(sqrt(5))x ?
The solution for (D^2+5)y=cos(sqrt(5))x is y=c_{1}cos(sqrt(5)x)+c_{2}sin(sqrt(5)x)+(cos(sqrt(5))x)/5