What is the solution for (d^2y)/(dx^2)+y-1=0,y(1)=0 ?

The solution for (d^2y)/(dx^2)+y-1=0,y(1)=0 is y=(cos(x)(-sin(1)c_{2}-1))/(cos(1))+c_{2}sin(x)+1

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(d^2y)/(dx^2)+y-1=0,y(1)=0

\frac{d ^{2} y}{d x ^{2}} + y - 1 = 0, y (1) = 0

y = \frac{cos ( x ) ( - sin ( 1 ) c _{2} - 1 )}{cos ( 1 )} + c_{2} sin (x) + 1

Solution steps

\frac{d ^{2} y}{d x ^{2}} + y - 1 = 0

Solve linear ODE:

y = \frac{cos ( x ) ( - sin ( 1 ) c _{2} - 1 )}{cos ( 1 )} + c_{2} sin (x) + 1

y = \frac{cos ( x ) ( - sin ( 1 ) c _{2} - 1 )}{cos ( 1 )} + c_{2} sin (x) + 1

y^{^{''}} - 4 y = (x^{2} - 5) sin (2 x)

D (x) = - 12 x + 850

y^{^{''}} + b^{2} y = cos (2 t), y (0) = 1

y^{^{''}} + 2 y^{^{'}} - 8 y = 2 t

y^{^{''}} + y = - 16 \cdot cos (3 x)

What is the solution for (d^2y)/(dx^2)+y-1=0,y(1)=0 ?
The solution for (d^2y)/(dx^2)+y-1=0,y(1)=0 is y=(cos(x)(-sin(1)c_{2}-1))/(cos(1))+c_{2}sin(x)+1