What is the solution for y^{''}-y=(e^x)/(x^2) ?

The solution for y^{''}-y=(e^x)/(x^2) is y=c_{1}e^x+c_{2}e^{-x}-e^{-x}\Ei(2x)

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y^{''}-y=(e^x)/(x^2)

y^{^{''}} - y = \frac{e ^{x}}{x ^{2}}

y = c_{1} e^{x} + c_{2} e^{- x} - e^{- x} Ei (2 x)

Solution steps

y^{''} (x) - y = \frac{e ^{x}}{x ^{2}}

Solve linear ODE:

y = c_{1} e^{x} + c_{2} e^{- x} - e^{- x} Ei (2 x)

y = c_{1} e^{x} + c_{2} e^{- x} - e^{- x} Ei (2 x)

y^{^{''}} - 9 y = 1, y^{^{'}} (0) = 10

y^{^{''}} + y = 9 e^{- 4 x}, y (0) = 0, y^{^{'}} (0) = 0

x^{^{''}} + 2 x^{^{'}} + 5 x = 10 cos (3 t)

y^{^{''}} - y^{^{'}} = 1, y (0) = 19, y^{^{'}} (0) = 1

d, d (x) = \frac{5}{4} x^{2} + 56 x^{4} + \frac{8}{x} - 9 x

What is the solution for y^{''}-y=(e^x)/(x^2) ?
The solution for y^{''}-y=(e^x)/(x^2) is y=c_{1}e^x+c_{2}e^{-x}-e^{-x}\Ei(2x)