What is the tangent of y=(16x)/(x^2+16),(-2,-8/5) ?

The tangent of y=(16x)/(x^2+16),(-2,-8/5) is y= 12/25 x-16/25

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tangent of y=(16x)/(x^2+16),(-2,-8/5)

tangent of

y = \frac{16 x}{x ^{2} + 16}, (- 2, - \frac{8}{5})

y = \frac{12}{25} x - \frac{16}{25}

Solution steps

Find the slope of

y = \frac{16 x}{x ^{2} + 16} : \frac{d y}{d x} = \frac{16 ( - x ^{2} + 16 )}{( x ^{2} + 16 ) ^{2}}

Compute the slope of

y = \frac{16 x}{x ^{2} + 16}

(- 2, - \frac{8}{5}) : m = \frac{12}{25}

Find the line with slope m=

\frac{12}{25}

and passing through

(- 2, - \frac{8}{5}) : y = \frac{12}{25} x - \frac{16}{25}

y = \frac{12}{25} x - \frac{16}{25}

y^{^{''}} - 9 y = 0, y (0) = 7

\int \frac{3}{( x + 3 ) ^{2}} d x

f (x) = 3^{x^{2} - x + 5}

\frac{d y}{d x} + 7 = e^{7 x + y - 5}

\int \frac{5}{x 25 - ( ln ( x ) ) ^{2}} d x

What is the tangent of y=(16x)/(x^2+16),(-2,-8/5) ?
The tangent of y=(16x)/(x^2+16),(-2,-8/5) is y= 12/25 x-16/25