What is the solution for d(x)=(2500)/(30(0.3+0.03)) ?

The solution for d(x)=(2500)/(30(0.3+0.03)) is x=c_{1}+252.52525…t

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d(x)=(2500)/(30(0.3+0.03))

d (x) = \frac{2500}{30 ( 0.3 + 0.03 )}

x = c_{1} + 252.52525 \dots t

Solution steps

d x = \frac{2500}{30 ( 0.3 + 0.03 )}

Solve linear ODE:

x = c_{1} + 252.52525 \dots t

x = c_{1} + 252.52525 \dots t

y^{^{''}} = 2 y - x

y^{^{''}} - y \cdot a + g = 0

y^{^{'''}} - 11 y^{^{''}} + 28 y^{^{'}} = 36 e^{x}, y^{^{'}} (0) = 26

y^{^{''}} - 2 y^{^{'}} + 2 y = e x sec (x)

y^{^{''}} - 10 y^{^{'}} + 24 y = 150 e^{t}

What is the solution for d(x)=(2500)/(30(0.3+0.03)) ?
The solution for d(x)=(2500)/(30(0.3+0.03)) is x=c_{1}+252.52525…t