What is the solution for y^{''}-y*a+g=0 ?

The solution for y^{''}-y*a+g=0 is y=c_{1}e^{sqrt(a)t}+c_{2}e^{-sqrt(a)t}+g/a

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-y*a+g=0

y^{^{''}} - y \cdot a + g = 0

y = c_{1} e^{a t} + c_{2} e^{- a t} + \frac{g}{a}

Solution steps

y^{''} (t) - y \cdot a + g = 0

Solve linear ODE:

y = c_{1} e^{a t} + c_{2} e^{- a t} + \frac{g}{a}

y = c_{1} e^{a t} + c_{2} e^{- a t} + \frac{g}{a}

y^{^{'''}} - 11 y^{^{''}} + 28 y^{^{'}} = 36 e^{x}, y^{^{'}} (0) = 26

y^{^{''}} - 2 y^{^{'}} + 2 y = e x sec (x)

y^{^{''}} - 10 y^{^{'}} + 24 y = 150 e^{t}

y^{^{''}} - 2 y^{^{'}} = 12 x + 10

y^{^{''}} + 2 y^{^{'}} + 17 y = 20 e^{t}, y (0) = 2, y^{^{''}} (0) = - 4

What is the solution for y^{''}-y*a+g=0 ?
The solution for y^{''}-y*a+g=0 is y=c_{1}e^{sqrt(a)t}+c_{2}e^{-sqrt(a)t}+g/a