What is the solution for (d^2y)/(dx^2)-(dy)/(dx)=-3 ?

The solution for (d^2y)/(dx^2)-(dy)/(dx)=-3 is y=c_{1}e^x+c_{2}+3x

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(d^2y)/(dx^2)-(dy)/(dx)=-3

\frac{d ^{2} y}{d x ^{2}} - \frac{d y}{d x} = - 3

y = c_{1} e^{x} + c_{2} + 3 x

Solution steps

\frac{d ^{2} y}{d x ^{2}} - \frac{d y}{d x} = - 3

Solve linear ODE:

y = c_{1} e^{x} + c_{2} + 3 x

y = c_{1} e^{x} + c_{2} + 3 x

y^{^{''}} + 4 y = 1, y (0) = 0, y^{^{'}} (0) = 1

x^{^{''}} + 4 x = 12 cos (t)

\frac{d ^{2} y}{d x ^{2}} - 3 \frac{d y}{d x} + 2 y = x^{2}

y^{^{''}} + 4 y = 4598 cos (2 x)

x^{^{''}} - 2 x^{^{'}} + 2 x = e^{- t} cos (2 t)

What is the solution for (d^2y)/(dx^2)-(dy)/(dx)=-3 ?
The solution for (d^2y)/(dx^2)-(dy)/(dx)=-3 is y=c_{1}e^x+c_{2}+3x