What is the solution for y^{''}-8y^'+16y=16x+7 ?

The solution for y^{''}-8y^'+16y=16x+7 is y=c_{1}e^{4x}+c_{2}xe^{4x}+x+15/16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-8y^'+16y=16x+7

y^{^{''}} - 8 y^{^{'}} + 16 y = 16 x + 7

y = c_{1} e^{4 x} + c_{2} x e^{4 x} + x + \frac{15}{16}

Solution steps

y^{''} (x) - 8 y^{'} (x) + 16 y = 16 x + 7

Solve linear ODE:

y = c_{1} e^{4 x} + c_{2} x e^{4 x} + x + \frac{15}{16}

y = c_{1} e^{4 x} + c_{2} x e^{4 x} + x + \frac{15}{16}

y^{^{''}} - 8 y^{^{'}} + 16 y = 16 x + 6

y^{^{''}} - 8 y^{^{'}} + 16 y = 16 x + 5

y^{^{'''}} - 3 y^{^{''}} + 3 y^{^{'}} - y = \frac{e ^{t}}{t}

y^{^{''}} - 2 y^{^{'}} - 15 y = 3 e^{5 t}

y^{^{'''}} + 4 y^{^{''}} - 5 y = x e^{x} + 8

What is the solution for y^{''}-8y^'+16y=16x+7 ?
The solution for y^{''}-8y^'+16y=16x+7 is y=c_{1}e^{4x}+c_{2}xe^{4x}+x+15/16