What is the solution for y^{''}-3y+2=x^2+2x+1 ?

The solution for y^{''}-3y+2=x^2+2x+1 is y=c_{1}e^{sqrt(3)x}+c_{2}e^{-sqrt(3)x}-(x^2)/3-(2x)/3+1/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-3y+2=x^2+2x+1

y^{^{''}} - 3 y + 2 = x^{2} + 2 x + 1

y = c_{1} e^{3 x} + c_{2} e^{- 3 x} - \frac{x ^{2}}{3} - \frac{2 x}{3} + \frac{1}{9}

Solution steps

y^{''} (x) - 3 y + 2 = x^{2} + 2 x + 1

Solve linear ODE:

y = c_{1} e^{3 x} + c_{2} e^{- 3 x} - \frac{x ^{2}}{3} - \frac{2 x}{3} + \frac{1}{9}

y = c_{1} e^{3 x} + c_{2} e^{- 3 x} - \frac{x ^{2}}{3} - \frac{2 x}{3} + \frac{1}{9}

y^{^{''}} - y^{^{'}} = x^{2} + 1

5 y^{^{''}} + 7 y^{^{'}} + 3 y = x^{2} + 2 e^{5 x}

(D^{2} - 2 D + 1) y = cosh (x)

x^{^{''}} + a^{2} x = a^{2} b - c

x^{^{''}} + x = sin (2 t), x (0) = 0, x^{^{'}} (0) = 0

What is the solution for y^{''}-3y+2=x^2+2x+1 ?
The solution for y^{''}-3y+2=x^2+2x+1 is y=c_{1}e^{sqrt(3)x}+c_{2}e^{-sqrt(3)x}-(x^2)/3-(2x)/3+1/9