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Popular >

x^{''}+4x=0

Solution

x^{^{''}} + 4 x = 0

Solution

x = c_{1} cos (2 t) + c_{2} sin (2 t)

Solution steps

x^{''} (t) + 4 x = 0

Solve linear ODE:

x = c_{1} cos (2 t) + c_{2} sin (2 t)

x = c_{1} cos (2 t) + c_{2} sin (2 t)

Graph

Popular Examples

16(d^4y)/(dx^4)+24(d^2y)/(dx^2)+9y=0

16 \frac{d ^{4} y}{d x ^{4}} + 24 \frac{d ^{2} y}{d x ^{2}} + 9 y = 0

y^{^{''}} - 5 y = 0

y^{''}+2y^'+y=0,y(0)=1,y^'(0)=1

y^{^{''}} + 2 y^{^{'}} + y = 0, y (0) = 1, y^{^{'}} (0) = 1

y^{^{''}} + y^{^{'}} - y = 0

y^{^{''''}} - 16 y = 0

Frequently Asked Questions (FAQ)

What is the solution for x^{''}+4x=0 ?
The solution for x^{''}+4x=0 is x=c_{1}cos(2t)+c_{2}sin(2t)