What is area 4cos(3x),4sin(6x),0, pi/6 ?

The answer to area 4cos(3x),4sin(6x),0, pi/6 is 2/3

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area 4cos(3x),4sin(6x),0, pi/6

area

4 cos (3 x), 4 sin (6 x), 0, \frac{π}{6}

\frac{2}{3}

Decimal Notation

0.66666 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{6}} ∣ 4 cos (3 x) - 4 sin (6 x) ∣ d x

Solve

\int_{0}^{\frac{π}{6}} ∣ 4 cos (3 x) - 4 sin (6 x) ∣ d x : \frac{2}{3}

The area is:

= \frac{2}{3}

8 arcsin (x^{4})

\int_{0.1}^{0.2} 300 x d x

\int cos (x) d x

tan (2) x^{2}

\frac{d}{d x} (5 - x^{\frac{2}{3}})

What is area 4cos(3x),4sin(6x),0, pi/6 ?
The answer to area 4cos(3x),4sin(6x),0, pi/6 is 2/3