Solution
Solution
Solution steps
Solve linear ODE:
Graph
Popular Examples
y^{''''}-8y^{'''}+16y^{''}=02y^{''}-5y^'+2y=09y^{''}+12y^'+4y=02y^{''}+8y^'+80y=0,y(0)=0,y^'(0)=0y^{''''}-14y^{''}-32y=0
Frequently Asked Questions (FAQ)
What is the solution for y^{''}+4y^'+2y=0 ?
The solution for y^{''}+4y^'+2y=0 is y=c_{1}e^{(-2+sqrt(2))t}+c_{2}e^{(-2-sqrt(2))t}