What is the solution for y^{''}+y^'+3y=0 ?

The solution for y^{''}+y^'+3y=0 is y=e^{-t/2}(c_{1}cos((sqrt(11)t)/2)+c_{2}sin((sqrt(11)t)/2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+y^'+3y=0

y^{^{''}} + y^{^{'}} + 3 y = 0

y = e^{- \frac{t}{2}} (c_{1} cos (\frac{11 t}{2}) + c_{2} sin (\frac{11 t}{2}))

Solution steps

y^{''} (t) + y^{'} (t) + 3 y = 0

Solve linear ODE:

y = e^{- \frac{t}{2}} (c_{1} cos (\frac{11 t}{2}) + c_{2} sin (\frac{11 t}{2}))

y = e^{- \frac{t}{2}} (c_{1} cos (\frac{11 t}{2}) + c_{2} sin (\frac{11 t}{2}))

y^{^{''}} + 225 y = 0

y^{^{''}} + 4 y^{^{'}} + 5 y = 0, y (0) = 2, y^{^{'}} (0) = - 7

2 y^{^{''}} + 2 y^{^{'}} + 3 y = 0

y^{^{''}} - 4 y^{^{'}} + 4 y = 0, y (0) = 2, y^{^{'}} (0) = 1

2 y^{^{''}} + 7 y^{^{'}} - 4 y = 0

What is the solution for y^{''}+y^'+3y=0 ?
The solution for y^{''}+y^'+3y=0 is y=e^{-t/2}(c_{1}cos((sqrt(11)t)/2)+c_{2}sin((sqrt(11)t)/2))