What is the solution for y^{'''}-3y^{''}-9y^'+27y=0 ?

The solution for y^{'''}-3y^{''}-9y^'+27y=0 is y=c_{1}e^{-3t}+c_{2}e^{3t}+c_{3}te^{3t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{'''}-3y^{''}-9y^'+27y=0

y^{^{'''}} - 3 y^{^{''}} - 9 y^{^{'}} + 27 y = 0

y = c_{1} e^{- 3 t} + c_{2} e^{3 t} + c_{3} t e^{3 t}

Solution steps

y^{'''} (t) - 3 y^{''} (t) - 9 y^{'} (t) + 27 y = 0

Solve linear ODE:

y = c_{1} e^{- 3 t} + c_{2} e^{3 t} + c_{3} t e^{3 t}

y = c_{1} e^{- 3 t} + c_{2} e^{3 t} + c_{3} t e^{3 t}

y^{^{''}} + 2 y^{^{'}} + y = 0, y^{1} (0) = x e^{- x}

8 \frac{d ^{2} y}{d x ^{2}} + 3 \frac{d y}{d x} + 9 y = 0

y^{^{'''}} + 4 y^{^{''}} + 3 y^{^{'}} = 0

y^{^{''}} = a y

y^{^{''}} - 14 y^{^{'}} + 51 y = 0

What is the solution for y^{'''}-3y^{''}-9y^'+27y=0 ?
The solution for y^{'''}-3y^{''}-9y^'+27y=0 is y=c_{1}e^{-3t}+c_{2}e^{3t}+c_{3}te^{3t}