What is the derivative of (2+x^2) ?

The derivative of (2+x^2) is 2(2+x)

What is the first derivative of (2+x^2) ?

The first derivative of (2+x^2) is 2(2+x)

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\frac{d}{d x} ((2 + x)^{2})

2 (2 + x)

Solution steps

\frac{d}{d x} ((2 + x)^{2})

Apply the chain rule:

2 (2 + x) \frac{d}{d x} (2 + x)

= 2 (2 + x) \frac{d}{d x} (2 + x)

\frac{d}{d x} (2 + x) = 1

= 2 (2 + x) \cdot 1

Simplify

= 2 (2 + x)

\int_{1}^{2} 2^{- θ} d θ

\frac{d ^{2}}{d x ^{2}} (\frac{x}{x ^{2} - 3})

x \to - 3 - lim (x^{3} + 27)

\int (a + \frac{b}{x - a})^{2} d x

f (x) = (\frac{x + 1}{x - 1})^{2}

What is the derivative of (2+x^2) ?
The derivative of (2+x^2) is 2(2+x)
What is the first derivative of (2+x^2) ?
The first derivative of (2+x^2) is 2(2+x)